Basic Trigonometry – Free Practice Questions

Basic Trigonometry is part of Maths (Quantitative Aptitude) in government exams such as SSC MTS, SSC CHSL, SSC CGL, RRB Group D / Level-1, RRB NTPC and others. This page has 234 free practice questions in English and Hindi, with correct answers and explanations and short revision notes.

मूल त्रिकोणमिति – हिंदी और अंग्रेज़ी में 234 निःशुल्क अभ्यास प्रश्न, उत्तर और व्याख्या के साथ।

Read short notes Practise with explanations Quick quiz (10 questions)Timed topic test

Questions: 234 · Sets of 50: 5 · Difficulty mix: 40 easy, 194 medium · Languages: English and Hindi

Sample Basic Trigonometry questions with answers

Q1. What is the value of sin 30°?

sin 30° का मान क्या है?

0
1/2
√3/2
1

Answer: 1/2. Standard value: sin 30° = 1/2.
मानक मान: sin 30° = 1/2

Q2. If sin θ = 40/41 and θ is acute, find cosec θ.

यदि sin θ = 40/41 और θ न्यून कोण है, तो cosec θ ज्ञात करें।

40/9
40/41
41/40
9/41

Answer: 41/40. Opposite = 40, hypotenuse = 41, so adjacent = √(41² − 40²) = 9. cosec θ = 41/40.
लंब = 40, कर्ण = 41, अतः आधार = √(41² − 40²) = 9। cosec θ = 41/40

Q3. If sin θ = 3/5 and θ is acute, find cot θ.

यदि sin θ = 3/5 और θ न्यून कोण है, तो cot θ ज्ञात करें।

Answer: 4/3. Opposite = 3, hypotenuse = 5, so adjacent = √(5² − 3²) = 4. cot θ = 4/3.
लंब = 3, कर्ण = 5, अतः आधार = √(5² − 3²) = 4। cot θ = 4/3

Q4. Find the value of cos² 45° × cot 45°.

cos² 45° × cot 45° का मान ज्ञात करें।

Answer: 1/2. cos² 45° = 1/2 and cot 45° = 1. So the value = 1/2.
cos² 45° = 1/2 और cot 45° = 1। अतः मान = 1/2

Q5. Find the value of sin² 60° × sec 60°.

sin² 60° × sec 60° का मान ज्ञात करें।

Answer: 3/2. sin² 60° = 3/4 and sec 60° = 2. So the value = 3/2.
sin² 60° = 3/4 और sec 60° = 2। अतः मान = 3/2

Q6. Find the value of sin² 45° × tan² 30°.

sin² 45° × tan² 30° का मान ज्ञात करें।

−1/12
1/6
2/3
7/6

Answer: 1/6. sin² 45° = 1/2 and tan² 30° = 1/3. So the value = 1/6.
sin² 45° = 1/2 और tan² 30° = 1/3। अतः मान = 1/6

Q7. If sin θ = 5/13 and θ is acute, find cos θ.

यदि sin θ = 5/13 और θ न्यून कोण है, तो cos θ ज्ञात करें।

13/12
5/13
12/13
13/5

Answer: 12/13. Opposite = 5, hypotenuse = 13, so adjacent = √(13² − 5²) = 12. cos θ = 12/13.
लंब = 5, कर्ण = 13, अतः आधार = √(13² − 5²) = 12। cos θ = 12/13

Q8. From a point on the ground 15 m away from the foot of a tower, the angle of elevation of the top of the tower is 45°. What is the height of the tower?

किसी मीनार के पाद से 15 मीटर दूर भूमि के एक बिंदु से मीनार के शिखर का उन्नयन कोण 45° है। मीनार की ऊँचाई कितनी है?

30 m
15 m
5√3 m
15√3 m

Answer: 15 m. Height = distance × tan θ. tan 45° = 1, so h = 15 m.
ऊँचाई = दूरी × tan θ। tan 45° = 1, अतः h = 15 मीटर।

Q9. Find the value of sin 30° × tan 0°.

sin 30° × tan 0° का मान ज्ञात करें।

Answer: 0. sin 30° = 1/2, tan 0° = 0. So the value = 0.
sin 30° = 1/2, tan 0° = 0। अतः मान = 0।

Q10. Find the value of cos 60° + tan 45°.

cos 60° + tan 45° का मान ज्ञात करें।

2 1/2
1
2
1 1/2

Answer: 1 1/2. cos 60° = 1/2, tan 45° = 1. So the value = 1 1/2.
cos 60° = 1/2, tan 45° = 1। अतः मान = 1 1/2।

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